Answer: c. 6.6 seconds
Step-by-step explanation:
Equation of direct variation between x and y : [tex]\dfrac{x_1}{y_1}=\dfrac{x_2}{y_2}------(1)[/tex]
Given : The Height of a wave in California varies directly with the seconds that pass by.
At 4 seconds, the wave is 6 feet high.
To find : Time taken to give you a wave that is 10 feet high.
Let Time taken to give you a wave that is 10 feet high. be x.
Put [tex]x_1=4\ , y_1=6\ \ \&\ x_2=x\ ,\ y_2=10[/tex] in (1)
[tex]\dfrac{4}{6}=\dfrac{x}{10}\\\\\Rightarrow\ x=\dfrac{4}{6}\times10=6.66666\approx6.6[/tex] [Nearest answer to the given option.]
Hence, after 6.6 seconds will give you a wave that is 10 feet high.
Correct answer is c. 6.6 seconds .
After 6.6 seconds will give you a wave that is 10 feet high.
Given ;
The Height of a wave in California varies directly with the seconds that pass by.
At 4 seconds, the wave is 6 feet high.
We have to find : Time taken to give you a wave that is 10 feet high.
Equation of direct variation between x and y = [tex]\frac{x_1}{y_1} = \frac{x_2}{y_2}[/tex].
Let Time taken to give you a wave that is 10 feet high be x.
Then ,
[tex]x_1 = 4 , x_2= x \\ y_1 = 6 , y_2 = 10[/tex]
Putting the values in the equation of direct variation ;
[tex]\frac{x_1}{y_1} =\frac{x_2}{y_2}[/tex]
[tex]\\\frac{4}{x} = \frac{6}{10}[/tex]
x = [tex]\frac{20}{3}[/tex]
x = 6.6
Hence, after 6.6 seconds will give you a wave that is 10 feet high.
For the more information about Equation of direct variation click the link given below;
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