Answer:
We need 7.94 grams of Ca3(PO4)2
Explanation:
Step 1: Data given
Volume of Ca3(PO4)2 = 200 mL = 0.2 L
Molarity = 0.128 M
Molar mass of Ca3(PO4)2 = 310.18 g/mol
Step 2: Calculate moles of Ca3(PO4)2
Moles = molarity * volume
Moles Ca3(PO4)2 = 0.128 M * 0.2 L
Moles Ca3(PO4)2 = 0.0256 moles
Step 3: Calculate mass of Ca3(PO4)2
Mass Ca3(PO4)2 = moles Ca3(PO4)2 * molar massCa3(PO4)2
Mass Ca3(PO4)2 = 0.0256 moles * 310.18 g/mol
Mass Ca3(PO4)2 = 7.94 grams
We need 7.94 grams of Ca3(PO4)2
