Answer:
Mass of present flour is less than the flour needed.
6/35 kilograms of flour is needed.
Step-by-step explanation:
Mass of flour required =[tex]\frac{3}{5} kg[/tex]
Mass of flour present =[tex]\frac{3}{7} kg[/tex]
[tex]\frac{3\times 7}{5\times 7} kg,\frac{3\times 5}{7\times 5} kg[/tex]
[tex]\frac{21}{35} kg,\frac{15}{35} kg[/tex]
[tex]\frac{21}{35} kg>\frac{15}{35} kg[/tex]
Mass of present flour present is less than the flour needed.
Amount of flour needed :
[tex]\frac{3}{5} kg-\frac{3}{7} kg[/tex]
[tex]\frac{3\times 7}{5\times 7} kg-\frac{3\times 5}{7\times 5} kg[/tex]
[tex]\frac{21}{35} kg-\frac{15}{35} kg[/tex]
[tex]\frac{21}{35} kg-\frac{15}{35} kg=\frac{6}{35} kg[/tex]
6/35 kilograms of flour is needed.
