Answer:
(0,-1),(1,0),(2,1),(3,2)
Step-by-step explanation:
We are given that a relation
[tex]y=x+1[/tex]
We have to find the four points contained in the inverse
The given function is linear function
Therefore,
Domain of function=R
Range of function=R
[tex]x=y-1[/tex]
Now, replace x by y and y replace by x
[tex]y=x-1[/tex]
Now, substitute y[tex]=f^{-1}(x)[/tex]
[tex]f^{-1}(x)=x-1[/tex]
It is linear function and defined for all real values.
Substitute x=0
[tex]f^{-1}(0)=-1[/tex]
Substitute x=1
[tex]f^{-1}(1)=1-1=0[/tex]
[tex]f^{-1}(2)=2-1=1[/tex]
[tex]f^{-1}(3)=3-1=2[/tex]
Therefore, four points contained in the inverse (0,-1),(1,0),(2,1) and (3,2)
