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200 mL of an ideal gas is placed in a piston and is held at a pressure of 500 torr. If the temperature is held constant and the pressure is increased to 650 torr, what is the new volume of the gas?

Respuesta :

Answer:

V₂=153.84 m L

Explanation:

Given that

Initial volume ,V₁ = 200 m L

Initial pressure ,P₁= 500 torr

Final pressure P₂ = 650 torr

Lets take the final volume =V₂

Given that process occurs at constant temperature and we know that for constant temperature process

P₁ V₁ = P₂ V₂

[tex]V_2=\dfrac{P_1V_1}{P_2}[/tex]

Now by putting the values

[tex]V_2=\dfrac{500\times 200}{650}\ mL[/tex]

V₂=153.84 m L

Therefore the new volume of the gas will be 153.8 4mL.

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