35. Two variables, x and y, appear to be exponentially related. The regression equation for ln y on x is ln y = 1.7 + .45x. What is the predicted value of y when x = .72?

Respuesta :

Answer:

[tex]y=7.57[/tex]

Step-by-step explanation:

Two variables, x and y, appear to be exponentially related. The regression equation for ln y on x is [tex]ln y = 1.7 + .45x[/tex]

we need to predict the value of y when x=0.72

plug in the value of x in the given equation

[tex]ln y = 1.7 + .45x[/tex]

[tex]ln y = 1.7 + .45(0.72)[/tex]

[tex]ln y = 1.7 + 0.324[/tex]

[tex]ln y = 2.024[/tex]

[tex]y=e^{2.024}[/tex]

[tex]y=7.57[/tex]