Answer:
Question 3:
AC = 3 yd.
m∠B = 37°
m∠C = 53°
Question 4;
GH = 8 km.
m∠H = 62°
m∠I = 28°
Step-by-step explanation:
Question 3:
The length AC
[tex]AC = 5*sin B.[/tex]
And the angle B
[tex]\boxed{\angle B=cos^{-1}(\frac{4}{5} )=36.87^o\approx 37^o.}[/tex]
Therefore
[tex]\boxed{AC = 5*sin(37^o)= 3yd}[/tex]
And the angle C:
[tex]\boxed{\angle C=sin^{-1}(\frac{4}{5} )=53.13^o \approx 53^o}[/tex]
Question 4:
The side GH
[tex]GH =17\:sin(I)[/tex]
The angle I is
[tex]\boxed{\angle I=cos^{-1}(\frac{15}{17} )=28.07^o\approx 28^o}[/tex]
Therefore,
[tex]\boxed{GH =17\:sin(I)=17sin(28^o)=8km}[/tex]
And the angle H:
[tex]\boxed{\angle H=sin^{-1}(\frac{15}{17} )=61.927^o\approx 62^o}[/tex]
