Respuesta :
These are the following steps to find the no solution for the given inequalities.
Part 1 ; Given Equation ; y < 2x-4
y > 2x+1
From the equation 2 putting the value of y in equation 1
= 2x+1 = 2x-4
= 2x-2x = -4-1
= 0 = -5
The given equation has no solution.
Equation; 2x + y ≥ 3
y ≥ −2x − 3
From the equation 2 putting the value of y in equation 1
= 2x-2x-3 = 3
= 0= 3+3
= 0 = 0
So , the given equation has no solution.
Equation ; 4x + 4y < 16
x > y + 16
From the equation 2 putting the value of x in equation 1
= 4( y + 16 ) + 4y = 16
= 4y+ 64 + 4y = 16
= 8y = 16-64
= 8y = -48
= y = [tex]\frac{-48}{8}[/tex]
= y = -6
Put y=-6
Then x = -6 + 16
x = 10
The equation has solution x = 10 and y = -6 .
Equation ; y < −6x −24
y < 6x + 6
Put the value of y in the equation 1 from equation 2
= 6x + 6 = -6x - 24
= 12x = -30
= x = [tex]\frac{-30}{12}[/tex] = [tex]\frac{-15}{6}[/tex]
Put the value of x in the equation 1
y = ([tex]-6(\frac{-15}{6}) - 24[/tex]
y = 15 - 24
y = -9
The equation has solution y = -9 and x =[tex]\frac{-15}{6}[/tex].
The First and second system of inequalities are correct which has no solution.
For more information about system of inequalities click the link given below
https://brainly.com/question/19935456
