Answer:
total friction is 0.9903 m
Explanation:
given data
diameter D = 100 mm = 0.1 m
discharge Q = 4 L/s = 0.004 m³/s
total length L = 300 m
roughness ∈ = 0.2 mm
solution
we get here total friction loss hf that is express as
hf = [tex]\frac{f*L*V^2}{2g*D}[/tex] ......................1
first we get here Reynold's no that is
Re = [tex]\frac{V*D}{\gamma}[/tex] ................2
Re = [tex]\frac{(\frac{0.004}{\pi*0.1^2/4})*0.1}{10^{-6}}[/tex]
Re = 50900
so here f is 0.025 by moody diagram
so put all value in equation 1 we get
hf = [tex]\frac{0.025*300*0.509^2}{2*9.81*0.1}[/tex]
hf = 0.9903 m
so total friction is 0.9903 m