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Lines AB and CD intersect at P. PR−→− is perpendicular to line AB, and the measure of ∠APD is 170°. A series of intersecting lines. What is the measure of ∠DPB?
A) 10
B) 20
C) 30
D) 40

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Answer:

The correct answer is option A.

Step-by-step explanation:

Given : line AB intersect CD at P. PR is perpendicular to AB.

∠APD = 170°

To find = ∠DPB =?

Solution :

line AB intersect CD at P:

So,∠APD =∠BPC = 170° ..[1]

(vertically opposite angles of two straight lines intersecting at common point are equal)

On line CD two angles are ∠BPC ,∠DPB

∠BPC + ∠DPB =180° (supplementary angles)

170°+ ∠DPB =180°

∠DPB =180° - 170° = 10°

So, the measure of ∠DPB is 10°.

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