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Suppose there are three cards in a deck: one marked with a 1, one marked with a 2, and one marked with a 5. You draw two cards at random and without replacement from the deck of three cards. The sample space S = {(1,2), (2,1),(1,5),(5,1),(2,5),(5,2)} consists of these six equally likely outcomes. Let X be the total of the two cards drawn. What would be the probabilities for X?

Respuesta :

Answer:

[tex]P(x=7) = 1/3\\P(x=6) = 1/3\\P(X=3) = 1/3[/tex]

Step-by-step explanation:

Given that there are three cards in a deck: one marked with a 1, one marked with a 2, and one marked with a 5

You draw two cards at random and without replacement from the deck of three cards. The sample space S = {(1,2), (2,1),(1,5),(5,1),(2,5),(5,2)} consists of these six equally likely outcomes

X = total of two cards can take values as

X    3    6    7

P   1/3  1/3  1/3

i.e. probability distribution for sum is

[tex]P(x=7) = 1/3\\P(x=6) = 1/3\\P(X=3) = 1/3[/tex]

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