Answer:
[tex]y = - \frac{3}{2}x + 2[/tex]
Step-by-step explanation:
We want to find the equation of the line that passes through:(4 -4) and (8, -10)
We first find the slope using
[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]
We plug in
[tex]x_1=4,x_2=-4,y_1=8,y_2=-10[/tex]
to get:
[tex]m = \frac{ - 10 - - 4}{8 - 4} = \frac{ - 6}{4} = - \frac{3}{2} [/tex]
We now use the point-slope formula:
[tex]y-y_1=m(x-x_1)[/tex]
This implies that:
[tex]y - - 4 = - \frac{3}{2} (x - 4)[/tex]
[tex]y = - \frac{3}{2} x + 6 - 4[/tex]
[tex]y = - \frac{3}{2}x + 2[/tex]
