To develop this problem we will apply the concepts related to the conservation of momentum. For this purpose, the initial momentum will be equivalent to the initial momentum of the two objects when they have the same speed. Mathematically this can be expressed as,
[tex]m_bv_b + m_wv_w = (m_b+m_w)v[/tex]
Where,
[tex]m_b[/tex] = Mass of bullet
[tex]v_b[/tex]= Velocity of bullet
[tex]m_w[/tex]= Mass of wooden block
[tex]v_w =[/tex]Velocity of Wooden block
Inititally [tex]v_w = 0[/tex] then we have that the expression can be rearrange to find the velocity of the bullet,
[tex]v_b = \frac{(m_b+m_w)v}{m_b}[/tex]
Replacing with our values
[tex]v_b = \frac{(15+5085)(0.94)}{15}[/tex]
[tex]v_b = 319.6m/s[/tex]
Therefore the velocity of the bullet before striking the block is 319.6m/s
The velocity of the bullet before striking the block is 319.6m/s.
The momentum neither be created nor be destroyed only transfer one form into another form.
Total momentum will be always conserved.
[tex]m_{b}v_{b}+m_{w}v_{w}=(m_{b}+m_{w})v[/tex]
Given that, [tex]m_{b}=15g,m_{w}=5085g,v=0.94m/s[/tex]
Substitute values in above relation and initially [tex]v_{w}=0[/tex]
[tex]v_{b}=\frac{(15+5085)*0.94}{15}\\ \\v_{b}=319.6m/s[/tex]
Learn more about the velocity here:
https://brainly.com/question/6504879
