Answer:
b) [tex]x=-4[/tex] is another zero of the polynomial
Step-by-step explanation:
Since you are given a set of options to choose from, a very simple way to find the zero of the polynomial is by simply plugging each value from the options and seeing which of them gives the answer 0.
[tex]f(x) = 2x^3+x^2-25x+12\\[/tex]
Using all the options:
[tex]a)\,f(-3) = 2(-3)^3+(-3)^2-25(-3)+12\\f(-3) = 42\\\\b)\,f(4) = 2(4)^3+(4)^2-25(4)+12\\f(4) = 56\\\\c)\,f(-4) = 2(-4)^3+(-4)^2-25(-4)+12\\f(-4) = 0\\\\d)\,f(12) = 2(12)^3+(12)^2-25(12)+12\\f(12) = 3312[/tex]
Now we know that at x = -4 the value of the polynomial f(x) is 0. hence
b) [tex]x=-4[/tex] is another zero of the polynomial
