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Prepare a 1.00 L of a 0.25 M solution of sodium carbonate. Determine the amount of sodium carbonate needed in correct significant figures.

Respuesta :

Neetoo

Answer:

Mass = 26.50 g

Explanation:

Given data:

Mass of sodium carbonate = ?

Molarity of solution = 0.25 M

Volume of solution = 1.00 L

Solution:

Molarity = number of moles / volume in litter

0.25 M = number of moles / 1.00 L

Number of moles = 0.25 M × 1.00 L

Number of moles = 0.25 mol

Mass:

Mass = number of moles × molar mass

Mass = 0.25 mol × 106 g/mol

Mass = 26.50 g

wkaliyah2

Answer:

0.168m

Explanation:

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