Answer:
[tex]2.26m/s^2[/tex]
Explanation:
Suppose the tension in the ribbon is T.
The upwards component of the tension = Tcos13
The horizontal component of the tension = Tsin13
The weight of the medal = mg
In a vertical direction, mg is balanced by Tcos13, so mg=Tcos13, so T = mg/cos13. The horizontal component of T is the force causing m to accelerate.
[tex]F = ma\\T\sin13^{\circ} = ma[/tex]
Substituting T= mg/cos13 gives:
[tex]\frac{mg}{cos13^{\circ}}sin13^{\circ} = ma[/tex]
[tex]m[/tex] cancels and you have
[tex]g\tan13 = a\\a=9.81\tan13^{\circ} \approx 2.26m/s^2[/tex]
