The surface tension of water in air is approximately 0.0756 N-m. If theatmospheric pressure is 101 kPa (abs), what is the pressure inside a droplet 0.254mmin diameter?(A) 99.83 kPa (abs) (B) 101.0 kPa (abs) (C) 101.5 kPa (abs) (D) 102.2 kPa (abs)

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matthewadeyinka10 matthewadeyinka10 · Answer 1 · 2020-01-10T17:24:53+01:00

Answer:

D

Explanation:

For a droplet which has only one surface.

P1 - P2 = 2T/r

Where

P1 and P2 are inside pressure? and outside pressure = 101kpa abs.

T - Surface tension = 0.0756N/m

r - droplet radius = 0.254mm/2 = 0.127mm = 0.000127m

P1 = (2 x 0.0756/0.000127) + 101000 = 102.19kpa

Therefore the inside pressure P1 = 102.2kpa abs

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batolisis batolisis · Answer 2 · 2022-03-29T17:09:25+02:00

The pressure inside a droplet of 0.254mm diameter is : ( D ) 102.2 kPa

Given data :

Surface tension of water in air ( T ) = 0.0756 N-m

Atmospheric pressure = 101 kPa = 101000 Pa

Given that the droplet has one surface

P₁ - P₂ = [tex]\frac{2T}{r}[/tex] --- ( 1 )

Where : r ( Radius ) = 0.254 / 2 = 0.000127 m, T = 0.0756 N-m, P₁ = ?

P₂ = 101000 Pa

therefore

P₁ = [tex]\frac{2T}{r} + P_{2}[/tex]

= [ ( 2 * 0.0756 ) / 0.000127 ] + 101000

= 102.2 kPa

Hence we can conclude that the pressure inside a droplet of 0.254mm diameter is 102.2 kPa

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