Answer:
option A
Explanation:
given,
height of the cliff = 20 m
initial speed = 10 m/s
distance from the edge of the base of the cliff = ?
now,
time taken to cover vertical distance
initial vertical speed = 0 m/s
using equation of motion
[tex]s = u t + \dfrac{1}{2}gt^2[/tex]
[tex]s =\dfrac{1}{2}gt^2[/tex]
[tex]t = \sqrt{\dfrac{2s}{g}}[/tex]
[tex]t = \sqrt{\dfrac{2\times 20}{9.8}}[/tex]
t = 2 s
in same time the ball will travel horizontal distance
horizontal velocity of ball = 10 m/s
distance = s x t
d = 10 x 2
d = 20 m
Hence, the correct answer is option A