Answer:
The energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom is [tex]2.66\times 10^{-20} Joule[/tex].
Absorption is taking place.
Explanation:
[tex]E_n=-13.6\times \frac{Z^2}{n^2}ev[/tex]
where,
[tex]E_n[/tex] = energy of [tex]n^{th}[/tex] orbit
n = number of orbit
Z = atomic number
Energy of n = 5 in an hydrogen atom:
[tex]E_5=-13.6\times \frac{1^2}{5^2}eV=-0.544 eV[/tex]
Energy of n = 2 in an hydrogen atom:
[tex]E_6=-13.6\times \frac{1^2}{6^2}eV=-0.378 eV[/tex]
Energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom = E
[tex]E=E_6-E_5=-0.378 eV-(-0.544 eV)=0.166 eV[/tex]
Positive value of energy means that absorption is taking place that electron excite from lower energy level to higher energy level by absorbing the energy.
[tex]eV=1.60218 \times 10^{-19} J[/tex]
[tex]E=0.166 eV=0.166\times 1.60218 \times 10^{-19} J[/tex]
E = [tex]2.66\times 10^{-20} Joule[/tex]
The energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom is [tex]2.66\times 10^{-20} Joule[/tex].