Respuesta :
Answer:
The net chemical reaction of the given process:
[tex]6MnCO_3(s)+3O_2(g)+8 Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)[/tex]
Explanation:
Step 1: Manganese (II) carbonate and oxygen react to form manganese (IV) oxide and carbon dioxide.The chemical reaction is given as:
[tex]2MnCO_3(s)+O_2(g)\rightarrow 2MnO_2(s)+2CO_2(g)[/tex]
Step 2:Manganese (IV) oxide and aluminum react to form manganese and aluminum oxide.The chemical reaction is given as:
[tex]3MnO_2(s)+4Al(s)\rightarrow 3Mn(s) +2Al_2O_3(s)[/tex]
On adding reactions of 3 × [1] + 2 × [2] , we get net chemical reaction of the given process:
[tex]6MnCO_3(s)+3O_2(g)+8 Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)[/tex]
According to reaction,6 moles of manganese(II0 carbonate recats with 3 moles of oxygen gas and 8 moles of aluminum to give 6 moles of manganese , 6 moles of carbon dioxide gas and 4 moles of aluminum oxide.