Sam divided a rectangle into 8 congruent rectangles that each have a area of 5 cm2. what is the area of the rectangle before it is divided?
Answer:
[tex]Area\ of\ the\ rectangle = 40\ cm^{2}[/tex]
Step-by-step explanation:
Given:
Sam divided a rectangle into 8 congruent rectangles that each have an area of [tex]5\ cm^{2}[/tex]
We need to find the area of the rectangle before Sam divided it.
The area of the rectangle before Sam divided is 8 times of the area of the congruent rectangles.
Area of the rectangle = [tex]8\times (area\ of\ congruent\ rectangles)[/tex]
Area of the congruent rectangle is [tex]5\ cm^{2}[/tex]
So the area of the rectangle is
Area of the rectangle = [tex]8\times 5[/tex]
Area of the rectangle = [tex]40\ cm^{2}[/tex]
Therefore the area of the rectangle before divided is [tex]40\ cm^{2}[/tex]
