Answer:
c. 23 m/s
Explanation:
[tex]\theta[/tex] = Angle of banking = 45°
r = Radius of turn = 52 m
g = Acceleration due to gravity = 9.81 m/s²
v = Velocity of car
As the car is tilted we have the relation
[tex]tan\theta=\dfrac{v^2}{rg}\\\Rightarrow v=\sqrt{tan\theta rg}\\\Rightarrow v=\sqrt{tan45\times 52\times 9.8}\\\Rightarrow v=22.57432\ m/s\approx 23\ m/s[/tex]
The velocity of the car is 23 m/s if the car is not slipping
