Answer:
616.3 rad/s²
Explanation:
Given that
t= 1.46 s
Initial angular velocity ,ωi = 0 rad/s
Final angular velocity ωf= 27000 rev/min
Angular speed in the rad/s given as
[tex]\omega_f=\dfrac{2\pi N}{60}\ rad/s[/tex]
Now by putting the values
[tex]\omega_f=\dfrac{2\times 27000}{60}\ rad/s[/tex]
ωf=900 rad/s
We know that (if acceleration is constant)
ωf=ωi + α t
α=Angular acceleration
900 = 0 + α x 1.46
[tex]\alpha=\dfrac{900}{1.46}\ rad/s^2\\\alpha=616.43\ rad/s^2[/tex]
Therefore the acceleration will be 616.3 rad/s²
