contestada

An environmental study in a community shows that the level of a certain pollutant in the air is L(P)=P‾‾√ parts per million (ppm), where P is the population in heads (h). The population of the community is P(t)=65t2+2500, where t is years (yr) after 2000. The population in 2007 was ____.

Respuesta :

JeanaShupp

Answer: The population in 2007 was 5685 .

Step-by-step explanation:

We are given that : The population of the community is [tex]P(t)=65t^2+2500[/tex]   (1)

, where t is years (yr) after 2000.

For year 2007 ,

t= 2007-2000 =7

Substitute t= 7 in (1) , we get

The population in 2007= [tex]P(7)=65(7)^2+2500[/tex]

⇒The population in 2007 [tex]=65(49)+2500[/tex]

⇒The population in 2007[tex]=3185+2500[/tex]

⇒The population in 2007 [tex]=5685[/tex]

Therefore ,  the population in 2007 was 5685 .

Otras preguntas