Answer:
48.1 kPa
Explanation:
Data Given
initial volume V1 of oxygen gas = 250 mL
initial pressure P1 of oxygen gas = 114 kPa
final volume V2 of oxygen gas = 593 mL
final pressure P2 oxygen gas = ?
Solution:
This problem will be solved by using Boyle's law equation at constant Temperature.
The formula used
P1V1 = P2V2
As we have to find out Volume, so rearrange the above equation
P2 = P1V1 / V2
Put value from the data given
P2 = 114 kPa x 250 mL / 593 mL
P2 = 48.1 kPa
So the final pressure required = 48.1 kPa
