Respuesta :
50 g of iron will react with [tex]4.1 \times 10^{23}[/tex] molecules of oxygen.
Explanation:
The relevant chemical equation for the chemical reaction given is
[tex]4Fe + 3O_2 = 2Fe_2O_3[/tex].
Here, 4 moles of iron reacts with 3 moles of oxygen gas to produce 2 moles of ferric oxide.
So, 1 mole of iron will react with [tex]\frac{3}{4}[/tex] moles of oxygen.
Atomic weight of iron is 55.
So 55 g of Iron has 1 mole iron in it.
So 50 g of Iron has 50/55 mole iron in it.
So [tex]\frac{50}{55}[/tex] mole of iron will react with [tex]\frac{50}{55} \times \frac{3}{4}[/tex] moles of oxygen = 0.68 moles of oxygen.
One mole of oxygen contains [tex]6.022 \times 10^{23}[/tex] molecules of oxygen.
So 0.68 moles of oxygen contains [tex]4.1 \times 10^{23}[/tex] molecules of oxygen.
Iron metal will react with oxygen to form rust called iron oxide.
It can be represented as:
4 Fe + 3 O₂ = 2 Fe₂O₃
According to the above reaction, 4 moles of iron will react with 3 moles of oxygen to form 2 moles of ferric oxide.
Hence, 1 mole of iron will react with [tex]\dfrac{3}{4}[/tex] moles of oxygen.
We know that the atomic weight of iron is 55.
We know that 1 mole of iron contains 55 g of iron.
So, 50 gm of iron will have [tex]\dfrac{50}{55}[/tex] moles of iron in it.
[tex]\dfrac{50}{55}[/tex] mole of iron will react with [tex]\dfrac{50}{55}\times\dfrac{3}{4}[/tex] moles of oxygen
= 0.68 moles
1 mole of oxygen contains 6.022 × 10²³ molecules of oxygen so, 0.68 moles of oxygen will contain:
= 0.68 × 6.022 × 10²³ molecules
= 4.1 × 10²³ molecules.
Therefore, 4.1 × 10²³ molecules of oxygen will be required to react with 50 gm of metal.
To learn more about moles, molecules refer the link:
https://brainly.com/question/19569195
