Respuesta :
Answer : The mass of nitrogen gas produced during the decomposition of [tex]Na_3N[/tex] are, 0.546 grams.
Solution : Given,
Mass of [tex]Na_3N[/tex] = 3.25 g
Molar mass of [tex]Na_3N[/tex] = 83 g/mole
Molar mass of [tex]N_2[/tex] = 28 g/mole
First we have to calculate the moles of [tex]Na_3N[/tex].
[tex]\text{ Moles of }Na_3N=\frac{\text{ Mass of }Na_3N}{\text{ Molar mass of }Na_3N}=\frac{3.25g}{83g/mole}=0.039moles[/tex]
Now we have to calculate the moles of [tex]MgO[/tex]
The balanced chemical reaction will be,
[tex]2Na_3N\rightarrow N_2+6Na[/tex]
From the balanced reaction we conclude that
As, 2 mole of [tex]Na_3N[/tex] react to give 1 mole of [tex]N_2[/tex]
So, 0.039 moles of [tex]Na_3N[/tex] react to give [tex]\frac{0.039}{2}=0.0195[/tex] moles of [tex]N_2[/tex]
Now we have to calculate the mass of [tex]N_2[/tex]
[tex]\text{ Mass of }N_2=\text{ Moles of }N_2\times \text{ Molar mass of }N_2[/tex]
[tex]\text{ Mass of }N_2=(0.0195moles)\times (28g/mole)=0.546g[/tex]
Therefore, the mass of nitrogen gas produced during the decomposition of [tex]Na_3N[/tex] are, 0.546 grams.
