Answer: (C) Sample minimum: 32, Sample maximum: 81 Q1:39.5, Median: 58, Q3: 74
Step-by-step explanation:
Five number summary for a data contains :
Minimum value
First quartile [tex](Q_1)[/tex]
Median
Third quartile [tex](Q_3)[/tex]
Maximum value.
Given data : 32, 34, 43, 55, 65, 75, 81, 79, 73, 61,47, 36
Arrange in order →32, 34, 36, 43,47, 55, 61, 65, 73, 75, 79, 81
Total values = 12 (even)
⇒ Median = Mean of the middle most two values.
[tex]=\dfrac{55+61}{2} =58[/tex]
First quartile = Median of first half (32, 34, 36, 43,47, 55)
[tex]Q_1=\dfrac{36+43}{2}=39.5[/tex]
Third quartile = Median of first half (61, 65, 73, 75, 79, 81)
[tex]Q_3=\dfrac{73+75}{2}=74[/tex]
Also, Sample Minimum value = 32
Sample Maximum value=81
Therefore , the five-number summary for this data :
Sample Minimum=32
Sample Maximum=81
Median = 58
[tex]Q_1=39.5[/tex]
[tex]Q_3=74[/tex]
Hence, the correct option is (C) Sample minimum: 32, Sample maximum: 81 Q1:39.5, Median: 58, Q3: 74
