Answer:
0.88752 kgm²
0.02236 Nm
Explanation:
m = Mass of ball = 1.2 kg
L = Length of rod = 0.86 m
[tex]\theta[/tex] = Angle = 90°
Rotational inertia is given by
[tex]I=mL^2\\\Rightarrow I=1.2\times 0.86^2\\\Rightarrow I=0.88752\ kgm^2[/tex]
The rotational inertia is 0.88752 kgm²
Torque is given by
[tex]\tau=FLsin\theta\\\Rightarrow \tau=2.6\times 10^{-2}\times 0.86sin90\\\Rightarrow \tau=0.02236\ Nm[/tex]
The torque is 0.02236 Nm
