Explanation:
a) The merry-go-round makes 3.0 revolutions in 6.0 seconds
Time taken for 3 revolutions = 6 s
Time taken for 1 revolution = 6÷3 = 2 s
That is period, T = 2 s
We know that
[tex]\texttt{Angular speed},\omega =\frac{2\pi }{T}[/tex]
Substituting
[tex]\texttt{Angular speed},\omega =\frac{2\pi }{2}=3.14rad/s\\\\\texttt{Angular speed},\omega =\frac{2\pi }{2\times 2\pi}=0.5revolutions/s[/tex]
Angular speed = 0.5 revolutions/second = 3.14 rad/s
