Answer:
32.7 grams of Zn will remained in the crucible after cooling.
Explanation:
[tex]2ZnS+3O_2 \rightarrow 2ZnO + 2SO_2 [/tex]..[1]
[tex]ZnO+C\rightarrow Zn+CO [/tex]..[2]
Adding [1] + 2 × [2] we get:
[tex]2ZnS+3O_2+2C \rightarrow 2Zn + 2CO+2SO_2 [/tex]..[3]
Moles of ZnS in crucible = 0.50 mol
According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.
Then 0.50 moles of ZnS will give:
[tex]\frac{2}{2}\times 0.50 mol=0.50 mol[/tex] of Zn.
Mass of 0.50 moles of Zn =
= 0.50 mol × 65.4 g/mol =32.7 g
32.7 grams of Zn will remained in the crucible after cooling.