A fuel pump at a gasoline station doesn't always dispense the exact amount displayed on the meter. When the meter reads 1.000 L, the amount of fuel a certain pump dispenses is normally distributed with a mean of 1 L and standard deviation of 0.05 L. Let X represent the amount dispensed in a random trial when the meter reads 1.000 L Find P(X > 1.05). You may round your answer to two decimal places

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Answer:

P(X > 1.05) = 1 - 0.8413 = 0.1587 = 15.87%.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 1, \sigma = 0.05[/tex]

Find P(X > 1.05).

This is 1 subtracted by the pvalue of Z when X = 1. So:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1.05 - 1}{0.05}[/tex]

[tex]Z = 1[/tex]

[tex]Z = 1[/tex] has a pvalue of 0.8413

So P(X > 1.05) = 1 - 0.8413 = 0.1587 = 15.87%.

The value of P(x > 1.05) is 0.16

The given parameters are:

[tex]\mathbf{\sigma = 0.05}[/tex] --- the standard deviation

[tex]\mathbf{\mu = 1.000}[/tex] --- the mean

[tex]\mathbf{x = 1.05}[/tex] --- the sample reading

Start by calculating the z-score for x = 1.05 using:

[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]

So, we have:

[tex]\mathbf{z = \frac{1.05 - 1}{0.05}}[/tex]

[tex]\mathbf{z = 1}[/tex]

So, we have:

[tex]\mathbf{P(x > 1.05) = P(z > 1)}[/tex]

From z table of probabilities, we have:

[tex]\mathbf{P(z > 1) = 0.1587}[/tex]

This means that:

[tex]\mathbf{P(x > 1.05) = 0.1587}[/tex]

Approximate

[tex]\mathbf{P(x > 1.05) = 0.16}[/tex]

Hence, the value of P(x > 1.05) is 0.16

Read more about probabilities at:

https://brainly.com/question/11234923