Answer:
The mass of the other ball = 90 g
Explanation:
From the law of conservation of momentum,
Total momentum before collision = total momentum after collision
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where m₁ = mass of the golf ball, m₂ = mass of the other ball, u₁ = initial velocity of the gulf ball, u₂ = initial velocity of the other ball, v₁ = final velocity of the gulf ball, v₂ = final velocity of the other ball.
Note: The other ball was at rest, therefore u₂ = 0 m/s
m₁u₁ = m₁v₁ + m₂v₂
making m₂ the subject of the equation above,
m₂ = (m₁u₁-m₁v₁)/v₂...................... Equation 1
Given: m₁ = 45 g, u₁ = 273 km/h, v₁ = -91 km/h(moves to the left), v₂ = 182 km/h
Substituting these values into equation 1
m₂ = [45×273 - 45(-91)]/182
m₂ = (12285 + 4095)/182
m₂ = 16380/182
m₂ = 90 g.
Thus the mass of the other ball = 90 g
Answer: M2 = 90g
Therefore, the mass of the other ball is 90g
Explanation:
According to the law of conservation of momentum.
M1U1 + M2U2 = M1V1 + M2V2 .....1
Where,
M1 and M2 are mass of golf ball and another ball
U1 and U2 are their initial velocities
V1 and V2 are their final velocities
From equation 1
M1U1 - M1V1 = M2V2 - M2U2
M1U1 - M1V1 = M2V2 - M2U2
M2 = (M1U1 - M1V1)/(V2-U2) .....2
Given;
M1 = 45g
U1 = 273km/h
V1 = -91km/h. (It moves to opposite direction)
U2 = 0
V2 = 182km/h
Substituting into eqn 2
M2 =(45×273 - 45 × -91)/(182-0)
M2 = 16380/182
M2 = 90g
Therefore, the mass of the other ball is 90g
