Circle K has a greater area and it is higher than circle J by 500.045 square centimeter
Solution:
The area of circle is given as:
[tex]A = \pi r^2[/tex]
Where "r" is the radius of circle
Also, Radius is given by:
[tex]diameter = \frac{radius}{2}[/tex]
Given that,
Diameter of circle J is 18 cm
Therefore,
[tex]radius = \frac{18}{2} = 9[/tex]
Substitute r = 9 in area formula
[tex]A = 3.14 \times 9^2\\\\A =3.14 \times 81 = 254.34[/tex]
Thus area of circle J is 254.34 square centimeter
Diameter of Circle K is 31 cm
[tex]radius = \frac{31}{2} = 15.5[/tex]
Substitute r = 15.5 in area formula
[tex]A = 3.14 \times (15.5)^2\\\\A = 3.14 \times 240.25\\\\A = 754.385[/tex]
Thus area of circle K is 754.385 square centimeter
On comparing the area of circle J and circle K, we find the area of circle K to be higher
Area of circle K - Area of circle J = 754.385 - 254.34 = 500.045
Thus circle K has a greater area and it is higher than circle J by 500.045 square centimeter
