Respuesta :
Answer:
The given expanded sum of the series is [tex]\sum\limits_{n=5}^{9}3n+2=115[/tex]
Step-by-step explanation:
Given problem can be written as
[tex]\sum\limits_{n=5}^{9}3n+2[/tex]
To find their sums:
Now expanding the series
That is put n=5,6,7,8,9 in the given summation
[tex]\sum\limits_{n=5}^{9}3n+2=[3(5)+2]+[3(6)+2]+[3(7)+2]+[3(8)+2]+[3(9)+2][/tex]
[tex]=[15+2]+[18+2]+[21+2]+[24+2]+[27+2][/tex]
[tex]=17+20+23+26+29[/tex] (adding the terms)
[tex]=115[/tex]
Therefore [tex]\sum\limits_{n=5}^{9}3n+2=115[/tex]
Therefore the given sum of the series is [tex]\sum\limits_{n=5}^{9}3n+2=115[/tex]
The given expanded sum of the series is [tex]\sum\limits_{n=5}^{9}3n+2=115[/tex]
