Answer:
Q = 4389 j
Explanation:
Given data:
Initial temperature = 30°C
Final temperature = -5.0 °C
Mass of water = 32.6 g
Energy in system = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Q = m.c. ΔT
ΔT = T2 - T1
ΔT =-5°C - 30°C
ΔT = 35°C
Q = m.c. ΔT
Q = 30.0 g. 4.18 j/g.°C . 35°C
Q = 4389 j
