19
.
| Pb + 2 HI → _Pbl, + 1_H,
a). How many moles of Pbl, are produced from the reaction of 28 moles of
HI?

Respuesta :

Answer:

no. of moles of PbI₂ = 14 moles

Explanation:

Data Given:

no. of moles of HI = 28 moles

no. of moles of Pbl₂ = ?

Reaction Given

        Pb + 2HI -------→ Pbl₂ + H₂

Solution:

To solve this problem we have to look at the reaction

Reaction:

                  Pb  +  2HI   -------→  Pbl₂  +  H₂

                            2 mol          1 mol

So if we look at the reaction 2 mole of hydrogen iodide (HI) gives 1 moles of Lead iodide (PbI₂), then how many moles of Lead iodide (PbI₂) will be produced by 28 moles of hydrogen iodide (HI)

For this apply unity formula

                      2 mole of HI  ≅  1 moles of PbI₂

                      28 mole of HI  ≅  X moles of PbI₂

By Doing cross multiplication

                      moles of PbI₂ = 28 moles x 1 moles / 2 mole

                      moles of PbI₂ = 14 mole

28 mole of HI will produce 14 moles of PbI₂