Answer:
[tex]4x + 3y = - 3[/tex]
Step-by-step explanation:
The line is parallel to 4x+3y=3.
We rewrite this line in slope intercept form to deduce our slope.
[tex]y = - \frac{4}{3} x + 3[/tex]
The slope is
[tex]m = - \frac{4}{3} [/tex]
The line passes through (-3,3) so we use the point-slope formula:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y - 3 = - \frac{4}{3} (x - - 3)[/tex]
We simplify to get:
[tex]y= - \frac{4}{3}x - 4 + 3[/tex]
[tex]y= - \frac{4}{3}x - 1[/tex]
We rewrite in standard form to get:
[tex]3y = - 4x - 3[/tex]
[tex]3y + 4x = - 3[/tex]
