Respuesta :
Answer:
The temperature of the gas is 767.36 Kelvins
Explanation:
Using ideal gas equation:
PV = nRT
[tex]T=\frac{PV}{nR}[/tex]
where,
P = Pressure of gas in an engine= [tex]28 atm[/tex]
V = Volume of gas in an engine= 0.045 L
n = number of moles of gas in an engine= 0.020 mol
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas in an engine= ?
Putting values in above equation, we get:
[tex]T=\frac{28 atm\times 0.045 L}{0.020 mol\times 0.0821 L.atm/mol.K}[/tex]
T = 767.36 Kelvins
The temperature of the gas is 767.36 Kelvins
Answer:
The temperature of the gas is 767.7 Kelvin
Explanation:
Step 1: Data given
The volume of the gas = 0.045 L
Pressure = 28 atm
Number of moles = 0.020 moles of gas
Step 2: Calculate the temperature of the gas
p*V = n*R*T
T = (p*V)/(n*R)
⇒ with p = the pressure = 28 atm
⇒ with V = the volume of the gas = 0.045 L
⇒ with n = the number of moles of gas = 0.020 moles
⇒ with R = the gas constant = 0.08206 L*atm/ K*mol
T = (28*0.045)/(0.020*0.08206)
T = 767.7 K
The temperature of the gas is 767.7 Kelvin
