Answer:
[tex]3\frac{3}{8}[/tex]
Step-by-step explanation:
Find the sum
[tex]1\frac{3}{4} +1\frac{5}{8}[/tex]
we know that
[tex]\frac{3}{4}=\frac{6}{8}[/tex]
substitute
[tex]1\frac{6}{8} +1\frac{5}{8}[/tex]
step 1
Separate the mixed number into a whole number and a fraction number
[tex]1+\frac{6}{8} +1+\frac{5}{8}[/tex]
step 2
Group the whole numbers an the fraction numbers
[tex](1+1)+(\frac{6}{8} +\frac{5}{8})[/tex]
step 3
Combine like terms
[tex](2)+(\frac{11}{8})[/tex]
Remember that
[tex]\frac{11}{8}=\frac{8}{8}+\frac{3}{8}=1+\frac{3}{8}[/tex]
substitute
[tex]2+1+\frac{3}{8}[/tex]
[tex]3+\frac{3}{8}=3\frac{3}{8}[/tex]
The answer is reasonable
Because
I know that 1 3/4 < 2 and 1 5/8 < 2
so
The sum of both numbers must be less than 4
