Lily has $2.75 in her pocket, consisting of dimes and quarters. If there are 17 coins in all, how many of each does she have?

Respuesta :

Answer:

There are 10 dimes and 7 quarters of coins in all she have.

Step-by-step explanation:

Given:

Lily has $2.75 in her pocket, consisting of dimes and quarters.

There are 17 coins in all.

Now, to find the number of coins each she have.

Let the dimes be [tex]x.[/tex]

And the quarters be [tex]y.[/tex]

So, the total number of coins:

[tex]x+y=17.[/tex].......(1)

[tex]x=17-y.[/tex]

The value of a dime = $0.10.

And the value of a quarter = $0.25.

Now, the total money Lily has in her pocket:

[tex]0.10x+0.25y=2.75.[/tex]

Putting the value in the place of [tex]x[/tex] we get:

[tex]0.10(17-y)+0.25y=2.75[/tex]

⇒ [tex]1.7-0.10y+0.25y=2.75[/tex]

⇒ [tex]1.7+0.15y=2.75[/tex]

Subtracting both sides by 1.7 we get:

⇒ [tex]0.15y=1.05[/tex]

Dividing both sides by 0.15 we get:

⇒ [tex]y=7.[/tex]

The number of quarters = 7.

Now, putting the value of [tex]y[/tex] in equation (1) we get:

[tex]x+y=17.[/tex]

[tex]x+7=17.[/tex]

Subtracting both sides by 7 we get:

⇒ [tex]x=10.[/tex]

The number of dimes = 10.

Therefore, there are 10 dimes and 7 quarters of coins in all she have.