The volume of the object must be no larger than [tex]11.15 m^3[/tex].
Explanation:
In order for an object to be able to float in water, its density must be equal or smaller than the water density.
The density of water is:
[tex]\rho = 1000 kg/m^3[/tex]
This means that the density of the object must be no larger than this value.
We also know that the density of an object is given by
[tex]\rho = \frac{m}{V}[/tex]
where
m is the mass of the object
V is its volume
For the object in this problem, the mass is
[tex]m=1.115\cdot 10^4 kg[/tex]
Therefore, we can re-arrange the equation to find its volume:
[tex]V=\frac{m}{\rho}=\frac{1.115\cdot 10^4}{1000}=11.15 m^3[/tex]
So, the volume of the object must be no larger than [tex]11.15 m^3[/tex].
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