The velocity of the eagle is 7.0 m/s
Explanation:
The motion of the fish is a projectile motion, which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction, where the horizontal velocity of the fish is equal to the horizontal velocity of the eagle
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
We start by analyzing the vertical motion, using the following suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where:
s = 6.1 m is the vertical displacement of the fish
u = 0 is the initial vertical velocity of the fish
[tex]a=g=9.8 m/s^2[/tex] is the acceleration of gravity
t is the time
Solving for t, we find the time of flight of the fish:
[tex]t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(6.1)}{9.8}}=1.12 s[/tex]
Now we know that during this time, the fish travels a horizontal distance of
x = 7.9 m
Therefore, the horizontal velocity of the fish is
[tex]v_x = \frac{x}{t}=\frac{7.9}{1.12}=7.0 m/s[/tex]
And therefore, this is the initial velocity of the eagle.
Learn more about projectile motion:
brainly.com/question/8751410
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