Answer:
6907
Step-by-step explanation:
reqired sample size is [tex](\frac{t}{b} )^{2} s^{2}[/tex]
where,
crititical value (t) = 1.96 for 95% conf.
margin of error (b) = 0.25
standard deviation (s) = 10.6
Za/2 = Z0.025 = 1.96
n ≥ [tex](\frac{1.96}{0.25} )^{2} 10.6^{2}[/tex]
n >= 6906.27
n = 6907
In the question above, the given statement represent the answer as (6907).
