(1) What is the distance between the points (–8, –2) and (–7, –2)?
A 1
B6
C10
D15


(2) What is the perimeter of rectangle ABCD shown on the coordinate plane?



5 units



6 units



8 units



10 units

Respuesta :

Answer:

The distance between points (- 8 , - 2) , ( - 7 , - 2) is 1 unit

Step-by-step explanation:

Given as :

The coordinate are

[tex]x_1[/tex] , [tex]y_1[/tex] = - 8 , - 2

[tex]x_2[/tex] , [tex]y_2[/tex] = - 7 , - 2

Let The distance between the points = d

So, d = [tex]\sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2} }[/tex]

Or, d = [tex]\sqrt{((-7) - (-8))^{2} + ((-2) - (-2))^{2} }[/tex]

Or, d =  [tex]\sqrt{(-7 + 8)^{2} + (- 2 + 2)^{2} }[/tex]

Or, d = [tex]\sqrt{(1)^{2} + (0)^{2} }[/tex]

Or, d = [tex]\sqrt{1 + 0}[/tex]

∴  d =  [tex]\sqrt{1}[/tex]

i.e d = 1

So, The distance between the points = d = 1 unit

Hence, The distance between points (- 8 , - 2) , ( - 7 , - 2) is 1 unit  Answer