Company A charges a $80 annual fee plus a $10/hr car share fee. Company B
charges $125 plus $5/hr. What is the minimum number of hours that a car
share needs to be used per year to make Company B a better deal?

Respuesta :

Answer:

The number of hours must be greater than 9 to make a Company B a better deal

Step-by-step explanation:

Let

x ----> the number of hours

y ----> the total charge in dollars

we know that

The linear equation in slope intercept form is equal to

[tex]y=mx+b[/tex]

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value of the linear equation

In this problem we have

Company A

The slope is equal to [tex]m=\$10\ per\ hour[/tex]

The y-intercept is equal to [tex]b=\$80[/tex]

so

The linear equation is equal to

[tex]y=10x+80[/tex] -----> equation A

Company B

The slope is equal to [tex]m=\$5\ per\ hour[/tex]

The y-intercept is equal to [tex]b=\$125[/tex]

so

The linear equation is equal to

[tex]y=5x+125[/tex] -----> equation B

If a Company B is a better deal

then

[tex]5x+125 < 10x+80[/tex]

solve for x

[tex]125-80 < 10x-5x[/tex]

[tex]45 < 5x[/tex]

[tex]9 < x[/tex]

Rewrite

[tex]x> 9\ hours[/tex]

therefore

The number of hours must be greater than 9 to make a Company B a better deal

Answer:

10

Step-by-step explanation:

APEX