Answer:
Therefore the length of AB is 15 unit.
Step-by-step explanation:
Given:
A ≡ ( -7 , 4 ) ≡ (x₁ , y₁)
B ≡ ( 8 , 4 ) ≡ (x₂ , y₂)
C ≡ ( 8 , -3 )
D ≡ ( -7 , -3 )
To Find:
Length of AB =?
Solution:
Distance Formula between two points is given as
[tex]l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}[/tex]
Substituting the values we get
[tex]l(AB) = \sqrt{((8-(-7))^{2}+(4-4)^{2} )}\\l(AB) = \sqrt{((15))^{2}+(0)^{2} )}\\l(AB)=\sqrt{225}=15\ unit[/tex]
Therefore the length of AB is 15 unit.
