Answer:
A) The circumference of the tire is approximately 90.12 in.
B) Ann can travel a distance of [tex]24332.4\ in[/tex] or [tex]618.04\ m[/tex] in one minute.
Step-by-step explanation:
Given,
Diameter of the tire = 28.7 in
Solving for part A.
We have to find out the circumference of the tire.
Since the tire is in circular shape.
So the circumference of the tire is equal to π multiplied with diameter.
On framing the above sentence in equation form, we get;
[tex]Circumference = \pi d[/tex]
On putting the values, we get;
[tex]Circumference = 3.14\times28.7=90.118\approx90.12\ in[/tex]
Hence The circumference of the tire is approximately 90.12 inches.
Solving for part B.
Now Given:
Number of revolutions = 270
Now we know that distance traveled is equal to circumference of the travel.
In 1 revolution = 90.12 inches
so in 270 revolutions = Distance traveled in 270 revolutions.
By Using Unitary method we get;
Distance traveled in 270 revolutions = [tex]90.12\times 270 = 24332.4\ in[/tex]
Now we know that 1 inch = 0.0254 m
So 24332.4 inch = Distance traveled in 1 minute
By Using Unitary method we get;
Distance traveled in 1 minute = [tex]0.0254\times 24332.4 = 618.04\ m[/tex]
Hence Ann can travel a distance of [tex]24332.4\ in[/tex] or [tex]618.04\ m[/tex] in one minute.