Answer:
2.6 moles are present in the given number of atoms of zinc.
Explanation:
It is known that 1 mole of any element contains Avagadro's number of atoms. So
[tex]1 mole of Zn = 6.022*10^{23} atoms[/tex]
Then,
[tex]1 atom of Zn = \frac{1}{6.022*10^{23} }[/tex] moles
As here it is given that there is 1.58 * [tex]10^{24}[/tex] atoms of Zinc, then the number of moles in these number of atoms will be
[tex]No. of moles in 1.58 *10^{24} atoms of Zn = \frac{1.58*10^{24} }{6.022*10^{23} }[/tex] moles
[tex]No. of moles = 2.6 moles[/tex]
Hence, there are 2.6 moles in 1.58 * 10^24 atoms of zinc
