The volume of the gas is [tex]7.6\cdot 10^{-4}m^3[/tex]
Explanation:
At standard temperature and pressure (stp), the volume occupied by 1 mole of an ideal gas is always equal to
[tex]V=22.4 L[/tex]
In this problem, we have an amount of moles of gas of
n = 0.034 mol
Since 1 mol of gas occupies a volume of 22.4 L, we can set up the following ratio:
[tex]\frac{1 mol}{22.4 L}=\frac{0.034 mol}{V}[/tex]
where V is the volume occupied by 0.034 mol of gas. Solving for V, we find
[tex]V=\frac{0.034 mol}{1 mol}(22.4 L)=0.76 L[/tex]
Or, in cubic metres,
[tex]V=0.76 L = 7.6\cdot 10^{-4}m^3[/tex]
Learn more about ideal gases:
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